Question
Solve the following quadratic equation by factorization.
x2 – 15x + 54 = 0

Answer


$\begin{array}{l}
x^2-15 x+54=0 \\
\Rightarrow x^2-6 x-9 x+54=0 \\
\Rightarrow x(x-6)-9(x-6)=0 \\
\Rightarrow(x-6)(x-9)=0 \\
x-6=0 \Rightarrow x=6 \\
x-9=0 \Rightarrow x=9
\end{array}$
Hence, $x=6$ and $x=9$ are roots of the equation.

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