Question
Solve the following quadratic equation:$6x^2 + 11x + 3 = 0$
✓
Answer
$6x^2 + 11x + 3 = 0$
$\Rightarrow 6x^2 + 9x + 2x + 3 = 0$
$\Rightarrow 3x(2x + 3) + 1(2x + 3) = 0$
$\Rightarrow (2x + 3)(3x + 1) = 0$
$\Rightarrow (2x + 3) = 0 or (3x + 1) = 0$
$\Rightarrow\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{-1}{3}$
Hence, $\frac{-3}{2}$ and $\frac{-1}{3}$ are the roots of $6x^2 + 11x + 3 = 0$
$\Rightarrow 6x^2 + 9x + 2x + 3 = 0$
$\Rightarrow 3x(2x + 3) + 1(2x + 3) = 0$
$\Rightarrow (2x + 3)(3x + 1) = 0$
$\Rightarrow (2x + 3) = 0 or (3x + 1) = 0$
$\Rightarrow\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{-1}{3}$
Hence, $\frac{-3}{2}$ and $\frac{-1}{3}$ are the roots of $6x^2 + 11x + 3 = 0$
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