Question
Solve the following quadratic equation:$\sqrt3\text{x}^2+\text{10x}+7\sqrt3=0$
✓
Answer
$\sqrt3\text{x}^2+\text{10x}+7\sqrt3=0$$\Rightarrow\sqrt3\text{x}^2+12\text{x}-2\text{x}-8\sqrt3=0$
$\Rightarrow\sqrt3\text{x}\big(\text{x}+4\sqrt3\big)-2\big(\text{x}+4\sqrt{3}\big)=0$
$\Rightarrow\big(\sqrt{3}\text{x}-2\big)\big(\text{x}+4\sqrt3\big)=0$
$\Rightarrow\sqrt3\text{x}-2=0$ or $\text{x}+4\sqrt3=0$
$\Rightarrow\text{x}=\frac{2}{\sqrt3}$ or $\text{x}=-4\sqrt3$
$\Rightarrow\sqrt3\text{x}\big(\text{x}+4\sqrt3\big)-2\big(\text{x}+4\sqrt{3}\big)=0$
$\Rightarrow\big(\sqrt{3}\text{x}-2\big)\big(\text{x}+4\sqrt3\big)=0$
$\Rightarrow\sqrt3\text{x}-2=0$ or $\text{x}+4\sqrt3=0$
$\Rightarrow\text{x}=\frac{2}{\sqrt3}$ or $\text{x}=-4\sqrt3$
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Shri Maniklal has purchased 300 shares of F.V. ₹ 100, for M.V. ₹ 120. Company has paid dividend at 7%. Complete the following activity to find the rate of return on his investment.
Activity :
F.V. = ₹ 100
Number of shares = 300
Market value = ₹ 120
(a) Sum invested = M.V. × No. of shares
$\therefore$ = ⬜ x ⬜
= ₹ 36,000
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F.V. = ₹ 100
Number of shares = 300
Market value = ₹ 120
(a) Sum invested = M.V. × No. of shares
$\therefore$ = ⬜ x ⬜
= ₹ 36,000
(b) Dividend per share $=$ F.V. × rate of dividend
= ⬜ x $\frac{⬜}{100} $
= ₹ 7
$\therefore \quad$ Total dividend received $=300 \times 7$
= ₹ ⬜
(c) Rate of return $=\frac{\text { Dividend income }}{\text { Sum invested }} \times 100$
$=\frac{2,100}{36,000} \times 100 $
= ⬜ %
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