Question
Solve the following quadratic equation:$\text{x}^2-\big(\sqrt3+1\big)\text{x}+\sqrt3=0$
✓
Answer
$\text{x}^2-\big(\sqrt3+1\big)\text{x}+\sqrt3=0$$\Rightarrow\text{x}^2-\sqrt3\text{x}-\text{x}+\sqrt3=0$
$\Rightarrow\text{x}\big(\text{x}-\sqrt3\big)-1\big(\text{x}-\sqrt3\big)=0$
$\Rightarrow\big(\text{x}-\sqrt3\big)\big(\text{x}-1\big)=0$
$\Rightarrow\text{x}-\sqrt3=0$ or $\text{x}-1=0$
$\Rightarrow\text{x}=\sqrt{3}$ or $\text{x}=1$
$\Rightarrow\text{x}\big(\text{x}-\sqrt3\big)-1\big(\text{x}-\sqrt3\big)=0$
$\Rightarrow\big(\text{x}-\sqrt3\big)\big(\text{x}-1\big)=0$
$\Rightarrow\text{x}-\sqrt3=0$ or $\text{x}-1=0$
$\Rightarrow\text{x}=\sqrt{3}$ or $\text{x}=1$
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