Question
Solve the following quadratic equation by using formula method:
$3 x^2+8 x+3=0$

Answer

$\frac{-4+\sqrt{7}}{3}$ and $\frac{-4-\sqrt{7}}{3}$

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The circumferences of circular faces of a frustum are 132 cm and 88 cm and its height is 24 cm. To find the curved surface area of the frustum complete the following activity.$\left(\pi=\frac{22}{7}\right)$

Circumference $_1=2 \pi r_1=132$
$r_1=\frac{132}{2 \pi}=\square$
Circumference $_2=2 \pi \mathrm{r}_2=88$
$r_2=\frac{88}{2 \pi}=\square$
Slant height of frustum, $l=\sqrt{h^2+\left(r_1-r_2\right)^2}$
$=\sqrt{\square \square^2+\square^2}$
$=\square c m$
Curved Surface area of frustum $=\pi\left(r_1+r_2\right)$ l
$=\pi \times \square \times \square$
$=\square \text { sq. } \mathrm{cm}$
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