Question
Solve the following quadratic equation using formula method only
$\sqrt{3} x^2+10 x-8 \sqrt{3}=0$
$\sqrt{3} x^2+10 x-8 \sqrt{3}=0$
✓
Answer
$\sqrt{3} x^2+10 x-8 \sqrt{3}=0$
$a=\sqrt{3} ; b=10 ; c=-\frac{8}{\sqrt{3}}$
$ D=b^2-4 a c$
$ =(10)^2-4(\sqrt{3})(-8 \sqrt{3})$
$=100+96 $
$=196$
$x =\frac{- b \pm \sqrt{ b ^2-4 ac }}{2 a}$
$ x=\frac{-10 \pm \sqrt{196}}{2 \sqrt{3}} $
$ x=\frac{-10+14}{2 \sqrt{3}}, x=\frac{-10-14}{2 \sqrt{3}} $
$x=\frac{4}{2 \sqrt{3}}, x=\frac{24}{2 \sqrt{3}} $
$x=\frac{2}{\sqrt{3}}, x=-\frac{12}{\sqrt{3}}$
$a=\sqrt{3} ; b=10 ; c=-\frac{8}{\sqrt{3}}$
$ D=b^2-4 a c$
$ =(10)^2-4(\sqrt{3})(-8 \sqrt{3})$
$=100+96 $
$=196$
$x =\frac{- b \pm \sqrt{ b ^2-4 ac }}{2 a}$
$ x=\frac{-10 \pm \sqrt{196}}{2 \sqrt{3}} $
$ x=\frac{-10+14}{2 \sqrt{3}}, x=\frac{-10-14}{2 \sqrt{3}} $
$x=\frac{4}{2 \sqrt{3}}, x=\frac{24}{2 \sqrt{3}} $
$x=\frac{2}{\sqrt{3}}, x=-\frac{12}{\sqrt{3}}$
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