Question
Solve the following quadratic equations by factorisation : x² = 3
✓
Answer
$\begin{aligned}
& x^2=3 \\
\therefore & x^2-3=0 \\
\therefore & x^2-(\sqrt{3})^2=0 \\
\therefore & (x+\sqrt{3})(x-\sqrt{3})=0 \\
\therefore & (x+\sqrt{3})=0 \text { or }(x-\sqrt{3})=0 \\
\therefore & x=-\sqrt{3} \text { or } x=\sqrt{3}
\end{aligned}$
$\therefore-\sqrt{3}$ and $\sqrt{3}$ are the roots of given quadratic equation.
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