Question
Solve the following quadratic equations by factorization:
$6x^2 + 11x + 3 = 0$
$6x^2 + 11x + 3 = 0$
✓
Answer
We have been given
$6x^2 + 11x + 3 = 0$
$6x^2 + 9x + 2x + 3 = 0$
$3x(2x + 3) + 1(2x + 3) = 0$
$(2x + 3)(3x + 1) = 0$
$2x + 3 = 0$
$\text{x}=\frac{-3}{2}$
Or, $3x + 1 = 0$
$\text{x}=\frac{-1}{3}$
Hence, $\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{-1}{3}$
$6x^2 + 11x + 3 = 0$
$6x^2 + 9x + 2x + 3 = 0$
$3x(2x + 3) + 1(2x + 3) = 0$
$(2x + 3)(3x + 1) = 0$
$2x + 3 = 0$
$\text{x}=\frac{-3}{2}$
Or, $3x + 1 = 0$
$\text{x}=\frac{-1}{3}$
Hence, $\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{-1}{3}$
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