Question
Solve the following simultaneous equation graphically.
x – 3y = 1; 3x – 2y + 4 = 0

Answer

The given simultaneous equations are
$x-3 y=1$
$\therefore \quad 3 y=x-1$
$\therefore \quad y=\frac{x-1}{3}$
x4-2-51
y1-1-20
(x, y)(4, 1)(-2, -1)(-5, -2)(1, 0)
$3 x-2 y+4=0$
$\therefore \quad 2 y=3 x+4$
$\therefore \quad y=\frac{3 x+4}{2}$
x0-22-4
y2-15-4
(x, y)(0, 2)(-2, -1)(2, 5)(-4, -4)
Image
The two lines intersect at point (-2, -1).
∴ x = -2 and y = -1 is the solution of the simultaneous equations x – 3y = 1 and 3x – 2p + 4 = 0.
 

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