Question
Solve the following simultaneous equation graphically.
x + y = 5; x – y = 3
x + y = 5; x – y = 3
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In $\triangle XDE , QR \| EF......... \square$
$\therefore$ $\frac{\square}{\square}=\frac{\square}{\square}...............(ii)\square$
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$\therefore \text { seg PR\|seg DE .......... }$
(converse of basic proportionality theorem)
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$\therefore \frac{ XP }{\square}=\frac{\square}{ QE }$
(Basic proportionality theorem)
In $\triangle XDE , QR \| EF......... \square$
$\therefore$ $\frac{\square}{\square}=\frac{\square}{\square}...............(ii)\square$
$\therefore$ $\frac{\square}{\square}=\frac{\square}{\square}...............$ from (i) and (ii)
$\therefore \text { seg PR\|seg DE .......... }$
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