Question
Solve the following simultaneous equations using Cramer’s rule.
x + 2y = –1; 2x – 3y = 12

Answer


$\begin{aligned} & x+2 y=-1 \\ & 2 x-3 y=12 \\ & D=\left[\begin{array}{cc}1 & 2 \\ 2 & -3\end{array}\right]=(1 \times-3)-(2 \times 2)=-3-4=-7 \\ & D_x=\left[\begin{array}{cc}-1 & 2 \\ 12 & -3\end{array}\right]=(-1 \times-3)-(2 \times 12)=3-24=-21 \\ & D_y=\left[\begin{array}{cc}1 & -1 \\ 2 & 12\end{array}\right]=(1 \times 12)-(-1 \times 2)=12+2=14 \\ & x=\frac{D_x}{D}=-\frac{21}{-7}=3 y=\frac{D_y}{D}=\frac{14}{-7}=-2 \\ & \therefore(x, y)=(3,-2) \text { is solution. }\end{aligned}$

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