Question
Solve the following system of equations graphically:
2x + 3y + 5 = 0,
3x - 2y - 12 = 0
2x + 3y + 5 = 0,
3x - 2y - 12 = 0
✓
Answer
$\text{2x}+\text{3y}+5=0$ $\Rightarrow\text{y}=\frac{-5-\text{2x}}{3}$
$\text{3x}-\text{2y}-12=0$ $\Rightarrow\text{y}=\frac{\text{3x}-12}{2}$
Since the two graph intersect at (2, -3), x = 2 and y = -3
|
x:
|
-4
|
-1
|
|
y:
|
1
|
-1
|
|
x:
|
0
|
4
|
|
y:
|
-6
|
0
|
Since the two graph intersect at (2, -3), x = 2 and y = -3
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