Question
Solve the inequality: $7 \leq \frac{(3 x+11)}{2} \leq 11$

Answer

We have $7 \leqslant \frac{{(3x + 11)}}{2} \leqslant 11$
$ \Rightarrow 14 \leqslant 3x + 11 \leqslant 22 \Rightarrow 3 \leqslant 3x \leqslant 11$
$ \Rightarrow 1 \leqslant x \leqslant \frac{{11}}{3}$

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