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P-1 Quadratic Equations — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsP-1 Quadratic Equations3 Marks
Question
Solve : x² + x + 5 = 0
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Answer


$\begin{array}{c}x^2+x+5=0 \text { comparing with } \\ a x^2+b x+c=0 \\ \text { we get } a=1, b=1, c=5, \\ \therefore b^2-4 a c=(1)^2-4 \times 1 \times 5 \\ =1-20 \\ =-19 \\ x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\ =\frac{-1 \pm \sqrt{-19}}{2 \times 1}\end{array}$
$=\frac{-1 \pm \sqrt{-19}}{2}$
But $\sqrt{-19}$ is not a real number. Hence roots of the equation are not real.

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