Some electric bulbs are connected in series across a $220\, V$ supply in a room. If one bulb is fused then remaining bulbs are connected again in series across the same supply. The illumination in the room will
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$P = \frac{{{V^2}}}{R}$ $ \Rightarrow $ $P \propto \frac{1}{R}$ ($V$ - constant)
When one bulb will fuse out resistance of the series combination will be reduced.
Hence from ${P_{Consumed}} \propto \frac{1}{R}$ illumination will increase.
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