MCQ
Some solid $N{H_4}HS$ is placed in a flask containing $0.5\, atm$ of $N{H_3}$, what would be pressures of $N{H_3}$ and ${H_2}S$ when equilibrium is reached $N{H_4}H{S_{(g)}}$ $\rightleftharpoons$ $N{H_{3(g)}} + {H_2}{S_{(g)}}$, ${K_p} = 0.11$
  • A
    $6.65$
  • $0.665$
  • C
    $0665$
  • D
    $66.5$

Answer

Correct option: B.
$0.665$
(b) ${K_p} = \frac{{{p^2}}}{4};\,\,0.11 = \frac{{{p^2}}}{4} \Rightarrow {p^2} = 0.44$

or $p = \sqrt {0.44} = 0.66444 \approx \,0.665\,atm$

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