$90=\sqrt{\frac{\mathrm{YA}}{\mathrm{m}}}=\sqrt{\frac{16 \times 10^{11} \times 10^{-6} \times \Delta l}{6 \times 10^{-3}}}$
$=\frac{8100 \times 3}{8} \times 10^{-8}=\Delta l=0.03\;mm$
The amplitude of the particle at $x =\frac{4}{3} \,cm$ will be........ $cm$.