MCQ
$\sqrt[3]{{(61 - 46\sqrt 5 )}} = $
- ✓$1 - 2\sqrt 5 $
- B$1 - \sqrt 5 $
- C$2 - \sqrt 5 $
- DNone of these
==> $61 - 46\sqrt 5 = {(a - \sqrt b )^3} = {a^3} + 3ab - (3{a^2} + b)\sqrt b $
==> $61 = {a^3} + 3ab,\,46\sqrt 5 = (3{a^2} + b)\,\sqrt b $
==> $61 = ({a^2} + 3b)\,a$, $23\sqrt {20} = (3{a^2} + b)\sqrt b $
So,$a = 1,\,\,b = 20$.
Therefore, $\sqrt[3]{{61 - 46\sqrt 5 }} = 1 - \sqrt {20} = 1 - 2\sqrt 5 $.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
($1$) The radius of the circle $C$ is. . . . . .
($2$) The value of $\alpha$ is. . . . .
Given the answer or qution ($1$) and ($2$)