MCQ
$\sqrt[4]{\sqrt[3]{2^2}}$ is equal to:
  • A
    $2^{-6}$
  • $2^{\frac{1}{6}}$
  • C
    $2^{6}$
  • D
    $2^{-\frac{1}{6}}$

Answer

Correct option: B.
$2^{\frac{1}{6}}$
$\sqrt[4]{\sqrt[3]{2^2}}=\sqrt[4]{(2)^{\frac{2}{3}}}$
$=(2)^{\frac{2}{3}\times\frac{1}{4}}$
$=(2)^{\frac{1}{6}}$

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