Question
$\square$ABCD is a parallelogram. Side BC intersects circle at point P. Prove that DC = DP.



Get the step-by-step solution for this question inside the Vidyadip app.
Get the answer in the appGenerate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Sr No. | FV | Share is at | MV |
| $(1)$ | Rs. 100 | Par | … |
| $(2)$ | … | Premium Rs. 500 | Rs. 575 |
| $(3)$ | Rs. 10 | … | Rs. 5 |
| x | $19$ | $21$ | $23$ | $25$ | $27$ | $29$ | $31$ |
| f | $13$ | $15$ | $16$ | $18$ | $16$ | $15$ | $13$ |
