Question
State and explain Work-Energy theorem.

Answer

Work done on a body is reflected as change in kinetic energy, according to Work-Energy theorem.
$\text{W}=\int\text{Fdx}=\int\text{m}\frac{\text{dv}}{\text{df}} \text{dx}$
$=\int\text{mv}\text{ dv}=\Big|\frac{1}{2}\text{mv}^2\Big|^\text{vf}_\text{vi}$
Work done  $=\frac{1}{2}\text{m}(\text{v}^2_\text{f}-\text{v}_\text{i}^2)$
$=\frac{1}{2}\text{mv}_\text{f}^2-\frac{1}{2}\text{mv}_\text{i}^2$
Work done = Change in kinetic energy.

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