State Gauss's law in electrostatics. - Vidyadip

Question

State Gauss's law in electrostatics.

✓

Answer

Gauss's law: The net flux through a closed surface in free space is related to the net charge qenci that is enclosed by that surface and is given by
$
\Phi=\oint \vec{E} \cdot \vec{d} s =\frac{q m }{ m }
$
where $eO$ is the permittivity of free space and the electric flux $\vec{E} \cdot \vec{d} s$ is integrated over the entire area of the surface.
[Note: The SI unit of electric flux is the newton metre squared per coulomb $\left( N \cdot m ^2 / C \right)$ or, equivalently, the voltmetre $V\vec{E} \cdot \overrightarrow{d \mathrm{~s}}m).$

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