Question
State, whether the following numbers is rational or not : $( 3 - \sqrt3 )^2$
✓
Answer
$( 3 - \sqrt3 ) = 3^2 - 2 ( 3 ) ( \sqrt3 ) + ( \sqrt3 )^2$
$= 9 - 6\sqrt3 + 3$
$= 12 - 6\sqrt3$
$= 6 ( 2 - \sqrt3 )$
Irrational number.
$= 9 - 6\sqrt3 + 3$
$= 12 - 6\sqrt3$
$= 6 ( 2 - \sqrt3 )$
Irrational number.
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