MCQ
Statement A (Assertion) : Consider the following frequency distribution:
Class interval10-1515-2020-2525-3030-35
Frequency591265

The modal class is $10-15$.
Statement $K$ (Keason) : The class having maximum frequency is called the modal class.
  • A
    Both assertion (A) and reason ( $R$ ) are true and reason $(R)$ is the correct explanation of assertion $(A)$.
  • B
    Both assertion (A) and reason ( $R$ ) are true and reason $(R)$ is not the correct explanation of assertion (A).
  • C
    Assertion $(A)$ is true but reason $(R)$ is false.
  • Assertion (A) is false but reason $(R)$ is true.

Answer

Correct option: D.
Assertion (A) is false but reason $(R)$ is true.
(d) : Clearly, Reason is true.
The maximum frequency is 12 , which lies in the interval $20-25$. So, the modal class is 20-25.
$\therefore \quad$ Assertion is false but Reason is true.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Directions : In the following questions, the Assertions $(A)$ and Reason $(s)\ (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following :
Assertion : lf the pair of lines are coincident, then we say that pair of linesis consistent and it has a unique solution.
Reason : If the pair of lines are parallel, then the pair has no solution and is called inconsistent pair of equations.
Directions: In the following questions, the Assertions $(A)$ and Reason $(s) \ (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion: $\frac{1}{(\text{x-1)}\text{(x-2)}}+\frac{1}{(\text{x-2)}\text{(x-3)}}=\frac{2}{3} (x \neq 1,2,3)$ is a quadratic equation.
Reason: An equation of the form $ax^2 + bx + c = 0$, where $a, b,c, € R$ is a quadratic equation.
Statement-1 (A): The sum of first $n$ even natural numbers is $n(n+1)$.
Statement-2 (R): The sum of first $n$ odd natural numbers is $n(n-1)$.
Statement-1 (A): If the centroid of the triangle having its vertices at $A(1, a), B(2, b)$ and $C\left(c^2-3\right)$ lies on $x$-axis, then $a+b=3$.
Statement-2 (R): On y-axis, $x$-coordmate of every point is zero.
Directions: In the following questions, the Assertions $(A)$ and Reason$(s) (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion: If $x ^6+1$ is divided by $x -1$, then the remainder is $2 $.
Reason: $p(x)=x^6+1$ when divided by $x-1$, then remainder $=p(1), p(1)=1^6+1=2$.
Directions : In the following questions, a statement of assertion $(A)$ is followed by a statement of reason $(R).$ Mark the correct choice as :
Assertion : $\frac{(\sin\theta-\cos\theta)(\sin\theta+\cos)}{(\cos\theta-\sin\theta)(\cos\theta+\sin\theta)}=-1.$
Reason : $\sin^{2}\theta+\cos^{2}\theta=-1.$
Assertion (A): Image of point (5, -16) under x-axis is (-5, 16).
Reason (R): To find image of point (x, y) under x-axis change the sign of y and to find image under y-axis change sign of x.
Statement-1 (A): If $P A$ and $P B$ are tangents drawn from an external point $P$ to a circle with centre $O$, then the quadrilateral $A O B P$ is cyclic.
Statement-2 (R): The angle between two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line segments joining the points of contact at the centre.
Directions : In the following questions, the Assertions $(A)$ and Reason $(s) \ (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion : The no. which are not exactly divisible by $2$ are known as odd no.
Reason : $-3, -15, 7, 9$ are the odd no.
Directions : In the following questions, the Assertions $(A)$ and Reason $(s)\ (R)$ have been put forward. Read both the statements carefully and choose the correct alternative from the following:
Assertion : The pair of equations $5x – 15y = 8$ and $3x – 9y = \frac{24}{5}$ has infinitely many solution.
Reason : $\frac{\text{a}_1}{\text{a}_2}=\frac{\text{b}_1}{\text{b}_2}\neq\frac{\text{c}_1}{\text{c}_2}$ it satisfy the condition of infinitely many solution.