MCQ
Stationary waves are set up in air column. Velocity of sound in air is $330 m/s$ and frequency is $165\,Hz$. Then distance between the nodes is ... $m$
- A$2$
- ✓$1 $
- C$0.5$
- D$4$
✓
Answer
Correct option: B.
$1 $
b
(b) $v = 330$$m/s$; $n = 165$$Hz$.
(b) $v = 330$$m/s$; $n = 165$$Hz$.
Distance between two successive nodes
= $\frac{\lambda }{2}$ $ = \frac{v}{{2n}} = \frac{{330}}{{2 \times 165}} = 1m$
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