Question
Subtract $\frac{1}{x^2+2}$ from $\frac{2 x^3+x^2+3}{\left(x^2+2\right)^2}$
✓
Answer
$\begin{aligned} & \frac{2 x^3+x^2+3}{\left(x^2+2\right)^2}-\frac{1}{x^2+2}=\frac{2 x^3+x^2+3-\left(x^2+2\right)}{\left(x^2+2\right)^2} \\ & =\frac{2 x^3+x^2+3-x^2-2}{\left(x^2+2\right)^2} \\ & =\frac{2 x^3+1}{\left(x^2+2\right)^2}\end{aligned}$
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