Question
Subtract:
$2 (ab + bc + ca)$ from $- ab - bc - ca$

Answer

We have,
$-ab - bc - ca - 2(ab + bc + ca)$
$= -ab - bc - ca - 2ab - 2bc - 2ca$
On combining the like terms.
$= -ab - 2ab - bc - 2bc - ca - 2ca$
$= -3ab - 3bc - 3ca$

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