Question
Subtract: $6 m^3+4 m^2+7 m-3$ from $3 m^3+4$
✓
Answer
$6m^3 + 4m^2 + 7m - 3$ from $3m^3 + 4$
$= (3m^3 + 4) - (6m^3 + 4m^2 + 7m - 3)$
$= 3m^3 + 4 - 6m^3 + 4m^2 + 7m - 3$
$= 3m^3- 6m3 - 4m^2 - 7m + 4 + 3$
$= - 3m^3 - 4m^2 - 7m + 7$
$= (3m^3 + 4) - (6m^3 + 4m^2 + 7m - 3)$
$= 3m^3 + 4 - 6m^3 + 4m^2 + 7m - 3$
$= 3m^3- 6m3 - 4m^2 - 7m + 4 + 3$
$= - 3m^3 - 4m^2 - 7m + 7$
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