Question
Subtract as indicated:$4\frac{3}{4}-2\frac{1}{6}$

Answer

$4\frac{3}{4}-2\frac{1}{6}$$=\frac{4\times4+3}{4}-\frac{2\times6+1}{6}$
$=\frac{19}{4}-\frac{13}{6}$
$=\frac{19\times3}{4\times3}-\frac{13\times2}{6\times2}$ (because LCM of 4 and 6 is 12)
$=\frac{57}{12}-\frac{26}{12}$
$=\frac{57-26}{12}$
$=\frac{31}{12}$

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