Question
Subtract:
$x^3+2 x^2 y+6 x y^2-y^3$ from $y^3-3 x y^2-4 x^2 y$

Answer

$x^3+2 x^2 y+6 x y^2-y^3$ from $y^3-3 x y^2-4 x^2 y$
$=y^3-3 x y^2-4 x^2 y-\left(x^3+2 x^2 y+6 x y^2-y^3\right)$
$=y^3-3 x y^2-4 x^2 y-x^3-2 x^2 y-6 x y^2+y^3$
$=2 y^3-9 x y^2-6 x^2 y-x^3$
$=-x^3+2 y^3-6 x^2 y-9 x y^2$

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