9. Hydricarbon — Chemistry STD 11 Science — Question

$\Psi_{2 s}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{ r }{ a _0}\right) e ^{- r / 2 a _0}$

At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$

${N_{2(g)}} + 3{H_{2(g)}} \rightleftharpoons \,2N{H_{3(g)}}$ at equilibrium at constant volume will lead to

$X \rightleftharpoons  Y + Z$        $...(i)$

$A \rightleftharpoons  2B$            $...(ii)$

are in the ratio $9 : 1.$ If degree of dissociation of $X$ and $A$ be equal, then total pressure at equilibrium $(i)$ and $(ii)$ are in the ratio