- A$Ph - Br , MeO ^{-} Na ^{+}$
- B$PhO ^{-} Na ^{+}, MeOH$
- ✓$PhO ^{-} Na ^{+}, MeBr$
- DBenzene, MeBr

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Reason : Zinc forms complex with $CuSO_4$
$(i)$ Pure solvent $\to$ separated solvent molecules $\Delta$ $H_1$
$(ii)$ Pure solute $\to$ separated solute molecules$\Delta$ $H_2$
$(iii)$ Separated solvent and solute molecules $\to$ solution $\Delta H_3$ Solution so formed will be ideal if
$\mathrm{Sn}(\mathrm{s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{s})$
the ratio $\frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is
(Given $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
| List-I (Element) | List-II (Electronic Configuration) | ||
| A. | N | I. | $[ Ar ] 3 d^{10} 4 s^2 4 p ^5$ |
| B. | S | II. | $[ Ne ] 3 s^2 3 p ^4$ |
| C. | Br | III. | $[ He ] 2 s^2 2 p ^3$ |
| D. | Kr | IV. | $[ Ar ] 3 d^{10} 4 s^2 4 p ^6$ |