MCQ
Sulphuric acid reacts with $PC{l_5}$ to give
- AThionyl chloride
- BSulphur monochloride
- ✓Sulphuryl chloride
- DSulphur tetrachloride
✓
Answer
Correct option: C.
Sulphuryl chloride
c
(c) $HO - S{O_2} - OH + PC{l_5}\, \to Cl - S{O_2} - OH + POC{l_3}+ HCl$
(c) $HO - S{O_2} - OH + PC{l_5}\, \to Cl - S{O_2} - OH + POC{l_3}+ HCl$
$HO - S{O_2} - OH + 2PC{l_5} \to \mathop {Cl - S{O_2} - Cl}\limits_{{\rm{Sulphuryl chloride}}} + 2POC{l_3} + 2HCl$
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