MCQ
$\sum_{\mathrm{k}=0}^{20}\left({ }^{20} \mathrm{C}_{\mathrm{k}}\right)^{2}$ is equal to :
  • A
    ${ }^{40} \mathrm{C}_{21}$
  • B
    ${ }^{40} \mathrm{C}_{19}$
  • ${ }^{40} \mathrm{C}_{20}$
  • D
    ${ }^{41} \mathrm{C}_{20}$

Answer

Correct option: C.
${ }^{40} \mathrm{C}_{20}$
c
$\sum_{\mathrm{k}=0}^{20}{ }^{20} \mathrm{C}_{\mathrm{k}} \cdot{ }^{20} \mathrm{C}_{20-\mathrm{k}}$

sum of suffix is const. so summation will be ${ }^{40} \mathrm{C}_{20}$

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