MCQ
Supposing the energy of fourth shell for hydrogen atom is $-25\, a.u$ (arbitary unit). What would be its potential energy in ground state
- A$-200$
- B$-50$
- ✓$-800$
- D$-400$
✓
Answer
Correct option: C.
$-800$
c
${E_4} = \frac{{{E_0}}}{{{n^2}}}$
${E_4} = \frac{{{E_0}}}{{{n^2}}}$
$E_0 = E_4 × n^2 = -25 \times 4^2 = -400$
$PE = 2\,T.E. = -2 \times 400 = -800$
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