Two massless springs with spring constants $2\,k$ and $2\,k$, carry $50\, g$ and $100 \,g$ masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be
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$V _{\max }=\omega A$
$\Rightarrow \frac{ A _{1}}{ A _{2}}=\frac{\omega_{2}}{\omega_{1}}=\sqrt{\frac{9}{2} \times \frac{1}{2}}=\frac{3}{2}$
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