15^ = - Vidyadip

MCQ

$\tan 15^\circ = $

A
$\frac{1}{3}$
B
$\sqrt 3 - 2$
✓
$2 - \sqrt 3 $
D
None of these

✓

Answer

Correct option: C.

$2 - \sqrt 3 $

c
(c) $\tan {15^o} = \tan ({45^o} - {30^o})$

$ = \frac{{1 - 1/\sqrt 3 }}{{1 + 1/\sqrt 3 }} = \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}} \times \frac{{\sqrt 3 - 1}}{{\sqrt 3 - 1}} $

$= 2 - \sqrt 3 $.

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