Question
$\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)$ का मुख्य मान है $-$ 

Answer

$(A)\ \frac{\pi}{8}$
$\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)$
$=\tan ^{-1}\left[\tan \left(\pi+\frac{\pi}{8}\right)\right]$
$=\tan ^{-1}\left[\tan \frac{\pi}{8}\right]$
$=\frac{\pi}{8}$
अतः विकल्प $(A)$ सही है।

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