MCQ
$\tan \,{20^o}\cot \,{10^o}\cot \,{50^o}$ is equal to
- A$\frac{1}{{\sqrt 3 }}$
- ✓$\sqrt 3 $
- C$\frac{{\sqrt 3 }}{4}$
- D$4\sqrt 3 $
$\tan \theta \tan (60-\theta) \tan (60+\theta)=\tan 3 \theta$
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| Height (in $cm$) | $160$ | $150$ | $152$ | $161$ | $156$ | $154$ | $155$ |
| No of students | $12$ | $8$ | $4$ | $4$ | $3$ | $3$ | $7$ |
The median of the distribution is