MCQ
$\tan 3A - \tan 2A - \tan A = $
  • $\tan 3A\tan 2A\tan A$
  • B
    $ - \tan 3A\tan 2A\tan A$
  • C
    $\tan A\tan 2A - \tan 2A\tan 3A - \tan 3A\tan A$
  • D
    None of these

Answer

Correct option: A.
$\tan 3A\tan 2A\tan A$
a
(a) Since $\tan \,\,3A = \frac{{\tan A + \tan 2A}}{{1 - \tan A\,\,\tan 2A}}$

$ \Rightarrow \,\,\tan \,\,3A - \tan \,\,2A - \tan A = \tan \,\,3A\,\tan \,\,2A\,\,\tan A$.

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