MCQ
$\tan 5x\tan 3x\tan 2x = $
- ✓$\tan 5x - \tan 3x - \tan 2x$
- B$\frac{{\sin 5x - \sin 3x - \sin 2x}}{{\cos 5x - \cos 3x - \cos 2x}}$
- C$0$
- Dએકપણ નહિ.
$\Rightarrow \tan 5x = \tan (3x + 2x)$
==> $\tan 5x = \frac{{\tan 3x + \tan 2x}}{{1 - \tan 3x\tan 2x}}$
==>$\tan 5x - \tan 5x\tan 3x\tan 2x = \tan 3x + \tan 2x$
==> $\tan 5x\tan 3x\tan 2x = \tan 5x - \tan 3x - \tan 2x$.
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