Download App

Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
$\tan \frac{A}{2}$ is equal to
  • A
    $\sqrt{\frac{1-\sin A}{1+\sin A}}$
  • B
    $\sqrt{\frac{1+\sin A }{1-\sin A }}$
  • ✓
    $\sqrt{\frac{1-\cos A}{1+\cos A}}$
  • D
    $\sqrt{\frac{1+\cos A}{1-\cos A}}$
✓

Answer

Correct option: C.
$\sqrt{\frac{1-\cos A}{1+\cos A}}$
(C)
$\tan \left(\frac{ A }{2}\right)=\frac{\sin \left(\frac{ A }{2}\right)}{\cos \left(\frac{ A }{2}\right)}=\sqrt{\frac{\frac{1-\cos A }{2}}{\frac{1+\cos A }{2}}}=\sqrt{\frac{1-\cos A }{1+\cos A }}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ" from Trigonometry – II→Trigonometry – II — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Similar questions

$\sin 20^{\circ} \sin 40^{\circ} \sin 60^{\circ} \sin 80^{\circ}=$
→
For which value of K, point (-8, 6) lies on the locus $\frac{x^2}{4}+\frac{y^2}{3}= K ?$
→
The value of $\tan 1^{\circ} \cdot \tan 2^{\circ} \tan 3^{\circ}$ equal to
→
The area of a triangle with vertices at $(-4, -1), (1, 2)$ and $(4, -3)$ is :
→
If $f (x)+2 f \left(\frac{1}{x}\right)=3 x, x \neq 0$, and $S =\{x \in R : f (x)= f (-x)\} ;$ then S
→
If $p+i q=\sqrt{\frac{a+i b}{c+i d}}$, where $p, q, a, b, c, d \in R$, then $\left(p^2+q^2\right)^2=$
→
$\frac{\cos 9^{\circ}+\sin 9^{\circ}}{\cos 9^{\circ}-\sin 9^{\circ}}=$
→
If the coordinates of the vertex and the focus of a parabola are $(-1, 1)$ and $(2, 3) $respectively, then the equation of its directrix is
→
The complete set of values of $k$, for which the quadratic equation $x^2− kx + k + 2 = 0$ has equal roots, consists of:
→
Centre of the ellipse $9 x^2+5 y^2-36 x-50 y-164=0$ is at
→