MCQ
$\tan \left[ {{{\sec }^{ - 1}}\sqrt {1 + {x^2}} } \right] = $
- A$\frac{1}{x}$
- ✓$x$
- C$\frac{1}{{\sqrt {1 + {x^2}} }}$
- D$\frac{x}{{\sqrt {1 + {x^2}} }}$
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