MCQ
Tangents drawn from the point $(- 8, 0)$ to the parabola $y^2\, = 8x$ touch the parabola at $P$ and $Q$. If $F$ is the focus of the parabola, then the area of the triangle $PFQ$ (in sq. units) is equal to
- ✓$48$
- B$32$
- C$24$
- D$64$
$T=0$
or $T = y{y_1} - 4\left( {x + {x_1}} \right)$
where $\left( {{x_1},{y_1}} \right) \equiv \left( { - 8,0} \right)$
$\therefore $ Equation becomes: $x=8$
Chord of contact is $x=8$
$\therefore $ Coordinates of point $P$ and $Q$ are $(8,8)$
and $(8,-8)$
and focus of the parabola is $F(2,0)$
$\therefore $ Area of triangle $PQF = \frac{1}{2} \times \left( {8 - 2} \right) \times \left( {8 + 8} \right)$
$ = 48$ sq. units
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