MCQ
$\tan\left(\frac{\pi}{4}+\theta\right)\tan\left(\frac{3\pi}{4}+\theta\right)$is equal to
  • A
    -2
  • -1
  • C
    1
  • D
    $0$

Answer

Correct option: B.
-1
(B)
$\tan\left(\frac{\pi}{4}+\theta\right)\tan\left(\frac{3\pi}{4}+\theta\right)$
$=\tan\left(\frac{\pi}{4}+\theta\right)\tan\left(\frac{\pi}{2}+\left(\frac{\pi}{4}+\theta\right)\right)$
$=\tan\left(\frac{\pi}{4}+\theta\right)\left\{-\cot\left(\frac{\pi}{4}+\theta\right)\right\}$
$\ldots\left[\because\tan\left(\frac{\pi}{2}+\alpha\right)=-\cot\alpha\right]$
$=-1$

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