MCQ
$\tan\left(\frac{19\pi}{3}\right) $ નું મુલ્ય=...............
- ✓$\sqrt 3$
- B$-\sqrt 3$
- C$\frac{1}{\sqrt 3}$
- D$-\frac{1}{\sqrt 3}$
$\tan\left(\frac{19\pi}{3}\right) =\tan\left(6\pi+\frac{\pi}{3}\right)\ \ \ \left(\because \frac{19}{3}=6\frac{1}{3}\right)$
$=\tan \frac{\pi}{3}$ ($\because \pi$મુખ્ય આવર્તમાન છે.)
$=\sqrt 3$
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(જ્યાં $[.]$ એ મહત્તમ પૂર્ણાક વિધેય છે )