Ten tuning forks are arranged in increasing order of frequency in such a way that any two consecutive tuning forks produce $4$ beats per second. The highest frequency is twice that of the lowest. Possible highest and lowest frequencies (in $Hz$ ) are ................
A$80$ and $404$
B$100$ and $50$
C$44$ and $22$
D$72$ and $36$
Medium
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D$72$ and $36$
d (d)
Let frequencies be $f_1, f_2 \ldots f_{10}$ -
So, $f_{10}=f_1+9 \times$ (number of beats)
$f_{10}=f_1+36$
Hence, answer must be $(d)$.
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