Question
$
\text { Find } x \text {, if } \cos (2 x-6)=\cos ^2 30^{\circ}-\cos ^2 60^{\circ}
$

Answer

$
\begin{aligned}
& \cos (2 x-6)=\cos ^2 30^{\circ}-\cos ^2 60^{\circ} \\
& \Rightarrow \cos (2 x-6)=\cos ^2\left(90^{\circ}-60^{\circ}\right)-\cos ^2 60^{\circ} \\
& \Rightarrow \cos (2 x-6)=\sin ^2 60^{\circ}-\cos ^2 60^{\circ} \\
& \Rightarrow \cos (2 x-6)=1-2 \cos ^2 60^{\circ}=1-2\left(\frac{1}{2}\right)^2=1-\frac{1}{2}=\frac{1}{2} \\
& \Rightarrow \cos (2 x-6)=\frac{1}{2} \\
& \Rightarrow \cos (2 x-6)=\cos 60^{\circ} \\
& \Rightarrow(2 x-6)=60^{\circ} \\
& \Rightarrow 2 x=66^{\circ} \\
& \Rightarrow x=33^{\circ}
\end{aligned}
$

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