MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the domain of the function:
  • A
    $(0, 3)$
  • B
    $(0, 3)$
  • $(-3, 3)$
  • D
    $(-3, 3)$

Answer

Correct option: C.
$(-3, 3)$
We know radical cannot be negative.
So, $9-\text{x}^2,\geq 0$
$ (3 - \text{x}) (3 + \text{x}) \geq $
$\Rightarrow (\text{x} - 3) (\text{x} + 3) \leq 0$
$ \Rightarrow \text{x} \in [-3,3].$

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