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Relations and Functions — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsRelations and Functions1 Mark
MCQ
$\text{f}(\text{x})=\sqrt{9-\text{x}^2}$. Find the range of the function:
  • A
    R
  • B
    R+
  • C
    [-3, 3]
  • ✓
    [0, 3]
✓

Answer

Correct option: D.
[0, 3]
Solution: (D) [0, 3]
We know, square root is always non-negative.$\sqrt{9-\text{x}^2}>0$.
So, the range of the function is set of positive real numbers from 0 to 3.

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